The fuel mix for a small engine contains only 2 ingredients: gasoline and oil. If the mix requires 5 ounces of gasoline for every 6 ounces of oil, how many ounces of gasoline are needed to make 33 ounces of fuel mix?

F. 3
G. 6
H. 15
J. 27.5
K. 165



Answer :

To determine how many ounces of gasoline are needed to make 33 ounces of fuel mix, we can follow these steps:

1. Understand the ratio of the ingredients:
The fuel mix requires 5 ounces of gasoline for every 6 ounces of oil. Therefore, the ratio of gasoline to oil is \( \frac{5}{6} \).

2. Calculate the total ratio of the fuel mix:
The total parts of the fuel mix includes both gasoline and oil. Therefore, the total parts = \( 5 + 6 = 11 \).

3. Establish the proportion:
Since the total fuel mix is composed of 11 parts (5 parts gasoline and 6 parts oil), we can find out how much gasoline is needed in 33 ounces of the fuel mix by using the ratio:
[tex]\[ \text{Gasoline needed} = \left( \frac{\text{Parts of gasoline}}{\text{Total parts in the mix}} \right) \times \text{Total ounces of fuel mix} \][/tex]
[tex]\[ \text{Gasoline needed} = \left( \frac{5}{11} \right) \times 33 \][/tex]

4. Perform the calculation:
[tex]\[ \text{Gasoline needed} = \frac{5}{11} \times 33 = 15 \text{ ounces} \][/tex]

Therefore, the number of ounces of gasoline needed to make 33 ounces of fuel mix is:

H. 15

This completes the solution.