Name these organic compounds:

[tex]\[
\begin{array}{c}
CH_3-CH=CH-CH_3 \\
\text{2-butene}
\end{array}
\][/tex]

[tex]\[
\begin{array}{c}
CH_3-C\equiv C-CH_3 \\
\text{2-butyne}
\end{array}
\][/tex]



Answer :

Sure, let's go through the process of naming the organic compounds step-by-step.

### Compound 1: [tex]\( \text{CH}_3 - \text{C} = \text{C} - \text{CH}_3 \)[/tex]

1. Identify the longest carbon chain containing the double bond:
Here, the longest chain contains 4 carbon atoms.

2. Number the chain from the end nearest the double bond:
The double bond is between the second and third carbon.

3. Name the parent hydrocarbon:
Since the chain has 4 carbon atoms, it is a derivative of butene. Since the double bond starts at the second carbon, this is 2-butene.

4. Identify and name the substituents:
There are no substituents in this structure.

Therefore, the name of [tex]\( \text{CH}_3 - \text{C} = \text{C} - \text{CH}_3 \)[/tex] is 2-butene.

### Compound 2: [tex]\( \text{CH}_3 - \text{C} \equiv \text{C} - \text{CH}_3 \)[/tex]

1. Identify the longest carbon chain containing the triple bond:
The longest chain again contains 4 carbon atoms.

2. Number the chain from the end nearest the triple bond:
The triple bond is between the second and third carbon.

3. Name the parent hydrocarbon:
Since the chain has 4 carbon atoms and contains a triple bond starting at the second carbon, it is a derivative of butyne.

Therefore, the name of [tex]\( \text{CH}_3 - \text{C} \equiv \text{C} - \text{CH}_3 \)[/tex] is 2-butyne.

So, the names of the compounds are:
1. 2-butene
2. 2-butyne