Which inequality has no solution?

A. [tex]6(x+2)\ \textgreater \ x-3[/tex]
B. [tex]3+4x \leq 2(1+2x)[/tex]
C. [tex]-2(x+6)\ \textless \ x-20[/tex]
D. [tex]x-9\ \textless \ 3(x-3)[/tex]



Answer :

To determine which inequality has no solution, we will analyze each inequality step-by-step.

### Inequality 1: [tex]\(6(x + 2) > x - 3\)[/tex]
1. Distribute the 6 on the left side:
[tex]\[ 6x + 12 > x - 3 \][/tex]
2. Subtract [tex]\(x\)[/tex] from both sides:
[tex]\[ 5x + 12 > -3 \][/tex]
3. Subtract 12 from both sides:
[tex]\[ 5x > -15 \][/tex]
4. Divide by 5:
[tex]\[ x > -3 \][/tex]
This inequality has a solution [tex]\(x > -3\)[/tex].

### Inequality 2: [tex]\(3 + 4x \leq 2(1 + 2x)\)[/tex]
1. Distribute the 2 on the right side:
[tex]\[ 3 + 4x \leq 2 + 4x \][/tex]
2. Subtract [tex]\(4x\)[/tex] from both sides:
[tex]\[ 3 \leq 2 \][/tex]
This is a contradiction because 3 is never less than or equal to 2. Therefore, this inequality has no solution.

### Inequality 3: [tex]\(-2(x + 6) < x - 20\)[/tex]
1. Distribute the [tex]\(-2\)[/tex] on the left side:
[tex]\[ -2x - 12 < x - 20 \][/tex]
2. Add [tex]\(2x\)[/tex] to both sides:
[tex]\[ -12 < 3x - 20 \][/tex]
3. Add 20 to both sides:
[tex]\[ 8 < 3x \][/tex]
4. Divide by 3:
[tex]\[ \frac{8}{3} < x \][/tex]
or
[tex]\[ x > \frac{8}{3} \][/tex]
This inequality has a solution [tex]\(x > \frac{8}{3}\)[/tex].

### Inequality 4: [tex]\(x - 9 < 3(x - 3)\)[/tex]
1. Distribute the 3 on the right side:
[tex]\[ x - 9 < 3x - 9 \][/tex]
2. Subtract [tex]\(x\)[/tex] from both sides:
[tex]\[ -9 < 2x - 9 \][/tex]
3. Add 9 to both sides:
[tex]\[ 0 < 2x \][/tex]
4. Divide by 2:
[tex]\[ 0 < x \][/tex]
or
[tex]\[ x > 0 \][/tex]
This inequality has a solution [tex]\(x > 0\)[/tex].

### Conclusion
The inequality that has no solution is:
[tex]\[ 3 + 4x \leq 2(1 + 2x) \][/tex]