Answer:
8 = (-1/3)(6) + b
8 = -2 + b
b = 10
y = (-1/3)x + 10
The correct answer is A.
Answer:
Step-by-step explanation:
To find the equation of a line that is perpendicular to y = 3x - 2, we first need to determine the slope of the given line. In this case, the slope of y = 3x - 2 is 3.
The slope of a line perpendicular to another line is the negative reciprocal of the original slope. So, the slope of the perpendicular line will be -1/3.
Next, we use the point-slope form of a linear equation to find the equation of the perpendicular line passing through point (6,8). The point-slope form is given by y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.
Substitute m = -1/3 and (x1, y1) = (6,8) into the point-slope form:
y - 8 = (-1/3)(x - 6)
y - 8 = (-1/3)x + 2
y = (-1/3)x + 10
Therefore, the equation of the line that is perpendicular to y = 3x - 2 and passes through point (6,8) is y = (-1/3)x + 10.