Slips of paper marked with the numbers 3, 4, 5, 6, and 7 are placed in a box. After being mixed, two slips are drawn simultaneously.

1. Write out the sample space with equally likely outcomes, if possible.
2. Give the value of [tex]n(S)[/tex] and tell whether the outcomes in [tex]S[/tex] are equally likely.
3. Write the indicated events below in set notation:

a. Both slips are marked with odd numbers.

b. One slip is marked with an odd number and the other is marked with an even number.

c. Both slips are marked with the same number.

What is the sample space?

A. [tex]S = \{(3, 4), (3, 5), (3, 6), (3, 7), (4, 5), (4, 6), (4, 7), (5, 6), (5, 7), (6, 7)\}[/tex]

B. [tex]S = \{(3, 4), (3, 6), (5, 4), (5, 6), (7, 4), (7, 6)\}[/tex]

C. [tex]S = \{(3, 5), (3, 7), (5, 7)\}[/tex]

D. [tex]S = \{3, 4, 5, 6, 7\}[/tex]

The value of [tex]n(S)[/tex] is ________



Answer :

To solve this problem, let's break it down step-by-step.

1. Sample Space (S):
- The sample space consists of all possible pairs of slips that can be drawn simultaneously.
- Given slips are marked with the numbers 3, 4, 5, 6, and 7.
- The pairs are formed by picking two different numbers from these slips.
- The possible pairs are:
[tex]\[ (3, 4), (3, 5), (3, 6), (3, 7), (4, 5), (4, 6), (4, 7), (5, 6), (5, 7), (6, 7) \][/tex]

Therefore, the sample space [tex]\(S\)[/tex] is:
[tex]\[ S = \{(3, 4), (3, 5), (3, 6), (3, 7), (4, 5), (4, 6), (4, 7), (5, 6), (5, 7), (6, 7)\} \][/tex]

2. Value of [tex]\(n(S)\)[/tex]:
- [tex]\(n(S)\)[/tex] represents the number of outcomes in the sample space.
- Counting the number of pairs listed above, we get:
[tex]\[ n(S) = 10 \][/tex]

3. Equally Likely Outcomes:
- Since the slips are drawn simultaneously and each slip is equally likely to be picked, the outcomes in [tex]\(S\)[/tex] are equally likely.

4. Events in Set Notation:

a. Both slips are marked with odd numbers:
- The odd numbers among the slips are 3, 5, and 7.
- Possible pairs of odd numbers are:
[tex]\[ (3, 5), (3, 7), (5, 7) \][/tex]

Therefore, the set notation for event [tex]\(A\)[/tex] is:
[tex]\[ A = \{(3, 5), (3, 7), (5, 7)\} \][/tex]

b. One slip is marked with an odd number and the other is marked with an even number:
- The odd numbers are 3, 5, 7 and the even numbers are 4, 6.
- Possible pairs where one slip is odd and the other is even are:
[tex]\[ (3, 4), (3, 6), (4, 5), (4, 7), (5, 6), (6, 7) \][/tex]

Therefore, the set notation for event [tex]\(B\)[/tex] is:
[tex]\[ B = \{(3, 4), (3, 6), (4, 5), (4, 7), (5, 6), (6, 7)\} \][/tex]

c. Both slips are marked with the same number:
- Since all numbers on the slips are distinct, it is not possible to draw two slips with the same number.

Therefore, the set notation for event [tex]\(C\)[/tex] is:
[tex]\[ C = \{\} \][/tex]

In summary:
- The correct sample space is:
[tex]\[ S = \{(3, 4), (3, 5), (3, 6), (3, 7), (4, 5), (4, 6), (4, 7), (5, 6), (5, 7), (6, 7)\} \][/tex]
- The value of [tex]\(n(S)\)[/tex] is 10.
- The outcomes in [tex]\(S\)[/tex] are equally likely.
- The sets representing the indicated events are:
[tex]\[ A = \{(3, 5), (3, 7), (5, 7)\} \][/tex]
[tex]\[ B = \{(3, 4), (3, 6), (4, 5), (4, 7), (5, 6), (6, 7)\} \][/tex]
[tex]\[ C = \{\} \][/tex]