Answer :

To solve the given system of linear equations:

[tex]\[ \begin{cases} y = 3x - 4 \\ y = -\frac{1}{2}x + 3 \end{cases} \][/tex]

we can use the method of setting the [tex]\( y \)[/tex]-values equal to each other since both equations are equal to [tex]\( y \)[/tex].

1. Set the equations equal to each other:

[tex]\[ 3x - 4 = -\frac{1}{2}x + 3 \][/tex]

2. Combine like terms:

First, let's get all the [tex]\( x \)[/tex]-terms on one side of the equation. We can start by adding [tex]\(\frac{1}{2}x\)[/tex] to both sides:

[tex]\[ 3x + \frac{1}{2}x - 4 = 3 \][/tex]

Combine the [tex]\( x \)[/tex]-terms on the left side. Note that [tex]\( 3x = \frac{6}{2}x \)[/tex], so:

[tex]\[ \frac{6}{2}x + \frac{1}{2}x - 4 = 3 \][/tex]

Combine the fractions:

[tex]\[ \frac{7}{2}x - 4 = 3 \][/tex]

3. Isolate the [tex]\( x \)[/tex]-term:

Add 4 to both sides of the equation:

[tex]\[ \frac{7}{2}x = 3 + 4 \][/tex]

Simplify the right side:

[tex]\[ \frac{7}{2}x = 7 \][/tex]

4. Solve for [tex]\( x \)[/tex]:

To isolate [tex]\( x \)[/tex], multiply both sides by the reciprocal of [tex]\(\frac{7}{2}\)[/tex], which is [tex]\(\frac{2}{7}\)[/tex]:

[tex]\[ x = 7 \cdot \frac{2}{7} \][/tex]

Simplify:

[tex]\[ x = 2 \][/tex]

5. Substitute [tex]\( x \)[/tex] back into one of the original equations to solve for [tex]\( y \)[/tex]:

Substitute [tex]\( x = 2 \)[/tex] into the first equation [tex]\( y = 3x - 4 \)[/tex]:

[tex]\[ y = 3(2) - 4 \][/tex]
[tex]\[ y = 6 - 4 \][/tex]
[tex]\[ y = 2 \][/tex]

Therefore, the solution to the system of equations is:

[tex]\[ (x, y) = (2, 2) \][/tex]

So, the point of intersection of the two lines, and thus the solution to the system, is [tex]\( (2.0, 2.0) \)[/tex].