Answer:
5.0×10⁵ J/kg
Explanation:
The specific latent heat of vaporization (L) is the amount of energy (E) per mass (m) needed for a liquid at its boiling point to change states into a vapor. The energy (E) absorbed by the boiling water is equal to the power (P) of the heater times the amount of time (t).
The amount of energy is:
E = Pt
E = (50 W) (50 s)
E = 2500 J
The specific latent heat of vaporization is:
L = E/m
L = (2500 J) / (0.005 kg)
L = 500,000 J/kg
L = 5.0×10⁵ J/kg
