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Give only one answer to each question.

1. Calculate the amount of substance in 15 grams of [tex]$CaCO_3$[/tex]. [tex]\([ Ca = 40, C = 12, O = 16 ]\)[/tex]

A. [tex]1.5 \, mol[/tex]

B. [tex]0.015 \, mol[/tex]

C. [tex]0.15 \, mol[/tex]

D. [tex]0.0015 \, mol[/tex]



Answer :

GinnyAnswer
To determine the amount of substance in 15 grams of [tex]\( \text{CaCO}_3 \)[/tex], follow these steps:

1. Calculate the Molar Mass of [tex]\( \text{CaCO}_3 \)[/tex]:
- The components of [tex]\( \text{CaCO}_3 \)[/tex] each have the following molar masses:
- Calcium (Ca) = 40 g/mol
- Carbon (C) = 12 g/mol
- Oxygen (O) = 16 g/mol (there are 3 oxygen atoms in [tex]\( \text{CaCO}_3 \)[/tex])

- Sum these values to find the molar mass of [tex]\( \text{CaCO}_3 \)[/tex]:
[tex]\[ \text{Molar mass of } \text{CaCO}_3 = 40 + 12 + (3 \times 16) = 100 \text{ g/mol} \][/tex]

2. Determine the Number of Moles in 15 Grams of [tex]\( \text{CaCO}_3 \)[/tex]:
- Use the formula for moles, which is:
[tex]\[ \text{Moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \][/tex]

- Substituting the given values:
[tex]\[ \text{Moles of } \text{CaCO}_3 = \frac{15 \text{ g}}{100 \text{ g/mol}} = 0.15 \text{ mol} \][/tex]

So, the amount of substance in 15 grams of [tex]\( \text{CaCO}_3 \)[/tex] is [tex]\( \boxed{0.15 \text{ mol}} \)[/tex].

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