1. Problem-solving:
Calculate the molarity of a solution made by dissolving 10 grams of [tex]\(K_2CO_3\)[/tex] in enough water to make 300 mL of solution. (Molar mass of [tex]\(K_2CO_3 = 138.2 \, g/mol\)[/tex]).



Answer :

To calculate the molarity of a solution, follow these steps:

1. Identify the given values:
- Mass of solute (solute here is [tex]\(K_2O_3\)[/tex]): 10 grams
- Volume of the solution: 300 milliliters
- Molar mass of the solute ([tex]\(CNO_3\)[/tex]): 101.1 grams per mole

2. Convert the volume of solution to liters:
- Volume in liters = Volume in milliliters / 1000
- Volume in liters = 300 ml / 1000
- Volume in liters = 0.3 liters

3. Calculate the number of moles of solute:
- Moles of solute = Mass of solute / Molar mass of solute
- Moles of solute = 10 grams / 101.1 grams per mole
- Moles of solute ≈ 0.09891196834817013 moles

4. Calculate the molarity of the solution:
- Molarity (M) = Moles of solute / Volume of solution in liters
- Molarity (M) = 0.09891196834817013 moles / 0.3 liters
- Molarity (M) ≈ 0.3297065611605671 M

Therefore, the molarity of the solution is approximately 0.3297 M.