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A car has a mass of [tex]$1.00 \times 10^3$[/tex] kilograms, and it has an acceleration of [tex]4.5 \, \text{meters/second}^2[/tex]. What is the net force on the car?

A. [tex]0.9 \times 10^3 \, \text{newtons}[/tex]
B. [tex]2.5 \times 10^3 \, \text{newtons}[/tex]
C. [tex]4.5 \times 10^3 \, \text{newtons}[/tex]
D. [tex]9.0 \times 10^3 \, \text{newtons}[/tex]
E. [tex]9.6 \times 10^3 \, \text{newtons}[/tex]



Answer :

GinnyAnswer
To determine the net force acting on a car, we can utilize Newton's second law of motion, which states that the net force [tex]\( F \)[/tex] on an object is the product of its mass [tex]\( m \)[/tex] and its acceleration [tex]\( a \)[/tex]. Mathematically, this relationship is expressed as:

[tex]\[ F = m \times a \][/tex]

We are given:
- The mass of the car, [tex]\( m = 1.00 \times 10^3 \)[/tex] kilograms
- The acceleration of the car, [tex]\( a = 4.5 \)[/tex] meters per second squared

Substituting these values into the formula, we get:

[tex]\[ F = (1.00 \times 10^3 \text{ kg}) \times (4.5 \text{ m/s}^2) \][/tex]

Performing the multiplication:

[tex]\[ F = 1.00 \times 4.5 \times 10^3 \][/tex]
[tex]\[ F = 4.5 \times 10^3 \text{ N} \][/tex]

Thus, the net force on the car is:

[tex]\[ 4.5 \times 10^3 \text{ newtons} \][/tex]

The correct answer is:
C. [tex]\( 4.5 \times 10^3 \)[/tex] newtons

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