Answer :
Let's solve the inequality step-by-step to determine how many pounds of oranges Antoine can buy.
Given inequality:
[tex]\[ 1.30x + 5.20 \leq 18.20 \][/tex]
1. Subtract [tex]\( 5.20 \)[/tex] from both sides:
[tex]\[ 1.30x + 5.20 - 5.20 \leq 18.20 - 5.20 \][/tex]
[tex]\[ 1.30x \leq 13.00 \][/tex]
2. Divide both sides by [tex]\( 1.30 \)[/tex]:
[tex]\[ \frac{1.30x}{1.30} \leq \frac{13.00}{1.30} \][/tex]
[tex]\[ x \leq 10 \][/tex]
Therefore, the inequality simplifies to [tex]\( x \leq 10 \)[/tex].
This means Antoine can buy 10 pounds or less of oranges.
So the correct answer is:
C. [tex]\( x \leq 10 \)[/tex]; Antoine can buy 10 pounds or less of oranges.
Given inequality:
[tex]\[ 1.30x + 5.20 \leq 18.20 \][/tex]
1. Subtract [tex]\( 5.20 \)[/tex] from both sides:
[tex]\[ 1.30x + 5.20 - 5.20 \leq 18.20 - 5.20 \][/tex]
[tex]\[ 1.30x \leq 13.00 \][/tex]
2. Divide both sides by [tex]\( 1.30 \)[/tex]:
[tex]\[ \frac{1.30x}{1.30} \leq \frac{13.00}{1.30} \][/tex]
[tex]\[ x \leq 10 \][/tex]
Therefore, the inequality simplifies to [tex]\( x \leq 10 \)[/tex].
This means Antoine can buy 10 pounds or less of oranges.
So the correct answer is:
C. [tex]\( x \leq 10 \)[/tex]; Antoine can buy 10 pounds or less of oranges.
Answer:
C. x ≤ 10; Antoine can buy 10 pounds or less of oranges.
Step-by-step explanation:
1.30x + 5.20 ≤18.20
To solve this inequality, subtract 5.20 from each side.
1.30x + 5.20-5.20 ≤18.20-5.20
1.30x ≤13.00
Divide each side by 1.30.
1.30x/1.3 ≤13.00/1.3
x ≤10.00
Antoine can buy 10 lbs or less.