Determine the compound type for the following formulas:

1. [tex]C_{12}H_{22}O_{11}[/tex] [tex]\square[/tex]
2. [tex]Mg(OH)_2[/tex] [tex]\square[/tex]
3. [tex]H_2O[/tex] [tex]\square[/tex]
4. [tex]Cu_3Zn_2[/tex] [tex]\square[/tex]
5. [tex]Au[/tex] [tex]\square[/tex]



Answer :

To determine the types of the given compounds, we need to classify each based on its chemical formula. Here's a step-by-step evaluation of each compound:

1. Compound: [tex]\( \mathbf{C_{12}H_{22}O_{11}} \)[/tex]
- This formula represents a molecule composed of 12 carbon (C) atoms, 22 hydrogen (H) atoms, and 11 oxygen (O) atoms.
- This type of compound is known as a molecular compound, specifically a sugar (sucrose).

Type: Molecular compound

2. Compound: [tex]\( \mathbf{Mg(OH)_2} \)[/tex]
- This formula includes magnesium (Mg) combined with hydroxide anions (OH).
- The metal (magnesium) forms ions with the hydroxide group, making this an ionic compound, specifically magnesium hydroxide.

Type: Ionic compound

3. Compound: [tex]\( \mathbf{H_2O} \)[/tex]
- This simple formula constitutes 2 hydrogen (H) atoms and 1 oxygen (O) atom.
- This is a molecular compound, known commonly as water.

Type: Molecular compound

4. Compound: [tex]\( \mathbf{Cu_3Zn_2} \)[/tex]
- The formula consists of copper (Cu) and zinc (Zn) atoms without clear ionic or covalent bonds.
- Such a composition indicates a metallic alloy, specifically brass.

Type: Metallic alloy

5. Compound: [tex]\( \mathbf{Au} \)[/tex]
- This formula includes just one element, gold (Au).
- Being a single element, it is classified simply as an element.

Type: Element

To summarize, the classifications of the given compounds are as follows:

- [tex]\( \mathbf{C_{12}H_{22}O_{11}} \)[/tex]: Molecular compound
- [tex]\( \mathbf{Mg(OH)_2} \)[/tex]: Ionic compound
- [tex]\( \mathbf{H_2O} \)[/tex]: Molecular compound
- [tex]\( \mathbf{Cu_3Zn_2} \)[/tex]: Metallic alloy
- [tex]\( \mathbf{Au} \)[/tex]: Element