Answer :
To determine which catalyzed reaction breaks up ozone, let's examine the given reactions.
1. [tex]\( 2 \text{H}_2\text{O}_2 (l) \xrightarrow{\text{Lus}} 2 \text{H}_2\text{O}(l) + \text{O}_2 \)[/tex]
- This reaction involves the decomposition of hydrogen peroxide into water and oxygen. Ozone is not involved in this reaction.
2. [tex]\( \text{O}_3 + \text{O} \xrightarrow{a} 2 \text{O}_2 \)[/tex]
- In this reaction, ozone ([tex]\( \text{O}_3 \)[/tex]) reacts with an oxygen atom ([tex]\( \text{O} \)[/tex]) to form two molecules of oxygen ([tex]\( \text{O}_2 \)[/tex]). This reaction directly involves the breakdown of ozone.
3. [tex]\( 2 \text{H}_2\text{O}_2 (aq) \xrightarrow{\text{BZt}_3} 2 \text{H}_2\text{O}(l) + \text{O}_2 \)[/tex]
- Similar to the first reaction, this reaction involves the decomposition of hydrogen peroxide in aqueous form, resulting in water and oxygen. Again, ozone is not involved in this reaction.
4. [tex]\( \text{O}_2 + 2 \text{SO}_2 \xrightarrow{\text{NO}} 2 \text{SO}_3 \)[/tex]
- This reaction involves the oxidation of sulfur dioxide ([tex]\( \text{SO}_2 \)[/tex]) to sulfur trioxide ([tex]\( \text{SO}_3 \)[/tex]) using oxygen ([tex]\( \text{O}_2 \)[/tex]). Ozone is not involved in this reaction either.
Among the given reactions, the second reaction clearly describes the breakup of ozone ([tex]\( \text{O}_3 \)[/tex]) to form oxygen molecules ([tex]\( \text{O}_2 \)[/tex]).
Thus, the reaction that breaks up ozone is:
[tex]\[ \text{O}_3 + \text{O} \xrightarrow{a} 2 \text{O}_2 \][/tex]
This corresponds to option 2.
1. [tex]\( 2 \text{H}_2\text{O}_2 (l) \xrightarrow{\text{Lus}} 2 \text{H}_2\text{O}(l) + \text{O}_2 \)[/tex]
- This reaction involves the decomposition of hydrogen peroxide into water and oxygen. Ozone is not involved in this reaction.
2. [tex]\( \text{O}_3 + \text{O} \xrightarrow{a} 2 \text{O}_2 \)[/tex]
- In this reaction, ozone ([tex]\( \text{O}_3 \)[/tex]) reacts with an oxygen atom ([tex]\( \text{O} \)[/tex]) to form two molecules of oxygen ([tex]\( \text{O}_2 \)[/tex]). This reaction directly involves the breakdown of ozone.
3. [tex]\( 2 \text{H}_2\text{O}_2 (aq) \xrightarrow{\text{BZt}_3} 2 \text{H}_2\text{O}(l) + \text{O}_2 \)[/tex]
- Similar to the first reaction, this reaction involves the decomposition of hydrogen peroxide in aqueous form, resulting in water and oxygen. Again, ozone is not involved in this reaction.
4. [tex]\( \text{O}_2 + 2 \text{SO}_2 \xrightarrow{\text{NO}} 2 \text{SO}_3 \)[/tex]
- This reaction involves the oxidation of sulfur dioxide ([tex]\( \text{SO}_2 \)[/tex]) to sulfur trioxide ([tex]\( \text{SO}_3 \)[/tex]) using oxygen ([tex]\( \text{O}_2 \)[/tex]). Ozone is not involved in this reaction either.
Among the given reactions, the second reaction clearly describes the breakup of ozone ([tex]\( \text{O}_3 \)[/tex]) to form oxygen molecules ([tex]\( \text{O}_2 \)[/tex]).
Thus, the reaction that breaks up ozone is:
[tex]\[ \text{O}_3 + \text{O} \xrightarrow{a} 2 \text{O}_2 \][/tex]
This corresponds to option 2.