Question:

If [tex]$0 \leq \theta \ \textless \ 2 \pi$[/tex] and [tex]-8 \cos^2 \theta + 7 = 1[/tex], determine the values of [tex]\theta[/tex]. Write your answers in order from least to greatest.

Provide your answer below:

[tex]\theta = \square , \square[/tex]



Answer :

To solve the equation [tex]\(-8 \cos^2 \theta + 7 = 1\)[/tex] for [tex]\(\theta\)[/tex] within the interval [tex]\([0, 2\pi)\)[/tex], we follow these steps:

1. Simplify the equation:

Starting with the given equation:
[tex]\[ -8 \cos^2 \theta + 7 = 1 \][/tex]

Subtract 7 from both sides of the equation:
[tex]\[ -8 \cos^2 \theta = -6 \][/tex]

Divide both sides by -8:
[tex]\[ \cos^2 \theta = \frac{6}{8} \][/tex]

Simplify the fraction:
[tex]\[ \cos^2 \theta = \frac{3}{4} \][/tex]

2. Find the values of [tex]\(\cos \theta\)[/tex]:

Take the square root of both sides:
[tex]\[ \cos \theta = \pm \sqrt{\frac{3}{4}} \][/tex]

Simplify the square root:
[tex]\[ \cos \theta = \pm \frac{\sqrt{3}}{2} \][/tex]

3. Determine the angles [tex]\(\theta\)[/tex]:

The cosine function provides us with two principal values for each solution:

- When [tex]\(\cos \theta = \frac{\sqrt{3}}{2}\)[/tex]:
[tex]\[ \theta = \frac{\pi}{6} \quad \text{and} \quad \theta = \frac{11\pi}{6} \][/tex]

- When [tex]\(\cos \theta = -\frac{\sqrt{3}}{2}\)[/tex]:
[tex]\[ \theta = \frac{5\pi}{6} \quad \text{and} \quad \theta = \frac{7\pi}{6} \][/tex]

4. Convert these values into decimal form to match the provided results:

[tex]\[ \begin{aligned} &\theta = \frac{\pi}{6} \approx 0.524 \\ &\theta = \frac{5\pi}{6} \approx 2.618 \\ &\theta = \frac{7\pi}{6} \approx 3.665 \\ &\theta = \frac{11\pi}{6} \approx 5.760 \\ \end{aligned} \][/tex]

5. Arrange these solutions from least to greatest:

So the values of [tex]\(\theta\)[/tex] are:
[tex]\[ \theta = 0.523598775598299, 2.61799387799149, 3.66519142918809, \text{and } 5.75958653158129 \][/tex]

Thus, the solution in the correct order is:

[tex]\[ \theta = 0.523598775598299, 2.61799387799149, 3.66519142918809, 5.75958653158129 \][/tex]