Answered

Select the correct answer.

Consider these functions:
[tex]\[
\begin{array}{l}
f(x) = 3x - 7 \\
g(x) = \frac{x+1}{x-1}
\end{array}
\][/tex]

What is the value of [tex]\( f(g(3)) \)[/tex]?

A. -1
B. 0
C. 3
D. 5



Answer :

GinnyAnswer
Let's determine the value of [tex]\( f(g(3)) \)[/tex] step-by-step by first evaluating [tex]\( g(3) \)[/tex], and then substituting that result into the function [tex]\( f(x) \)[/tex].

1. Evaluate [tex]\( g(3) \)[/tex]:
[tex]\[ g(x) = \frac{x+1}{x-1} \][/tex]
Substitute [tex]\( x = 3 \)[/tex]:
[tex]\[ g(3) = \frac{3 + 1}{3 - 1} = \frac{4}{2} = 2 \][/tex]

2. Evaluate [tex]\( f(g(3)) \)[/tex]:
From the previous step, we know [tex]\( g(3) = 2 \)[/tex]. Now, we need to find [tex]\( f(2) \)[/tex]:
[tex]\[ f(x) = 3x - 7 \][/tex]
Substitute [tex]\( x = 2 \)[/tex]:
[tex]\[ f(2) = 3 \cdot 2 - 7 = 6 - 7 = -1 \][/tex]

So, the value of [tex]\( f(g(3)) \)[/tex] is [tex]\( -1 \)[/tex].

Thus, the correct answer is:
A. -1

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