calculate
the
force
applied
to
an
object
with
a
mass
of
2kg
when
its
speed
increases
from
6m/s
to
14m/s
due
to
the
action
of
the
force
over
a
distance
of
5m.



Answer :

Answer: 32 N

Explanation:To calculate the force applied to the object, we can use the formula that relates force, mass, change in velocity, and distance:

Force

=

mass

×

(

final velocity

2

initial velocity

2

)

2

×

distance

Force=

2×distance

mass×(final velocity

2

−initial velocity

2

)

Given:

Mass (

m) = 2 kg

Initial velocity (

v

i

) = 6 m/s

Final velocity (

v

f

) = 14 m/s

Distance (

d) = 5 m

Let's substitute the given values into the formula:

Force

=

2

×

(

1

4

2

6

2

)

2

×

5

Force=

2×5

2×(14

2

−6

2

)

Calculate the values inside the parentheses first:

1

4

2

=

196

14

2

=196

6

2

=

36

6

2

=36

Now, subtract to find

2

2

v

f

2

−v

i

2

:

196

36

=

160

196−36=160

Now substitute back into the force formula:

Force

=

2

×

160

10

Force=

10

2×160

Force

=

320

10

Force=

10

320

Force

=

32

 N

Force=32 N

Therefore, the force applied to the object is

32

32 Newtons.