Let's analyze the relationship between speed and stopping distance.
1. The stopping distance of a vehicle is proportional to the square of the speed. This means that if you double your speed, the stopping distance becomes four times greater (2^2 = 4).
2. In this scenario, we're interested in what happens if the speed triples.
3. If the speed triples, the stopping distance becomes three times the speed squared. Mathematically, this is represented as [tex]\(3^2 = 9\)[/tex].
Therefore, if your speed triples, you will need nine times the distance to stop.
So, the correct answer is:
A. nine
