Answer :
To determine which compound is inorganic among the given options, let's analyze each compound and see whether it contains a carbon atom. Generally, compounds that contain carbon atoms are classified as organic compounds, while those without carbon atoms are classified as inorganic compounds.
A. [tex]\(C _6 H _{12} O _6\)[/tex]
This compound is glucose, which is a carbohydrate. It has carbon atoms in its structure, making it an organic compound.
B. [tex]\(KH _2 PO _4\)[/tex]
This compound is potassium dihydrogen phosphate. It does not contain any carbon atoms, classifying it as an inorganic compound.
C. [tex]\(CH _3 COOH\)[/tex]
This compound is acetic acid, which is an organic acid. It contains carbon atoms, making it an organic compound.
D. [tex]\(C _2 H _6\)[/tex]
This compound is ethane, which is a hydrocarbon. It has carbon atoms in its structure, making it an organic compound.
E. [tex]\(C _2 H _5 OH\)[/tex]
This compound is ethanol, which is an alcohol. It contains carbon atoms, making it an organic compound.
After analyzing all options, we find that:
- A. [tex]\(C _6 H _{12} O _6\)[/tex] is organic.
- B. [tex]\(KH _2 PO _4\)[/tex] is inorganic.
- C. [tex]\(CH _3 COOH\)[/tex] is organic.
- D. [tex]\(C _2 H _6\)[/tex] is organic.
- E. [tex]\(C _2 H _5 OH\)[/tex] is organic.
Therefore, the correct answer is:
B. [tex]\(KH _2 PO _4\)[/tex]
A. [tex]\(C _6 H _{12} O _6\)[/tex]
This compound is glucose, which is a carbohydrate. It has carbon atoms in its structure, making it an organic compound.
B. [tex]\(KH _2 PO _4\)[/tex]
This compound is potassium dihydrogen phosphate. It does not contain any carbon atoms, classifying it as an inorganic compound.
C. [tex]\(CH _3 COOH\)[/tex]
This compound is acetic acid, which is an organic acid. It contains carbon atoms, making it an organic compound.
D. [tex]\(C _2 H _6\)[/tex]
This compound is ethane, which is a hydrocarbon. It has carbon atoms in its structure, making it an organic compound.
E. [tex]\(C _2 H _5 OH\)[/tex]
This compound is ethanol, which is an alcohol. It contains carbon atoms, making it an organic compound.
After analyzing all options, we find that:
- A. [tex]\(C _6 H _{12} O _6\)[/tex] is organic.
- B. [tex]\(KH _2 PO _4\)[/tex] is inorganic.
- C. [tex]\(CH _3 COOH\)[/tex] is organic.
- D. [tex]\(C _2 H _6\)[/tex] is organic.
- E. [tex]\(C _2 H _5 OH\)[/tex] is organic.
Therefore, the correct answer is:
B. [tex]\(KH _2 PO _4\)[/tex]
