The gravitational force between the Earth and a certain satellite is 243 N. If the satellite drifted further away from Earth to a distance 4 times the original distance, what would be the new gravitational force between it and the Earth? (Round to the nearest whole number.)



Answer :

To determine the new gravitational force between the Earth and the satellite when the distance is increased by a factor of 4, follow these steps:

1. Understand the gravitational force law:
The gravitational force between two masses is inversely proportional to the square of the distance between them. This means if the distance is [tex]\( d \)[/tex], the gravitational force [tex]\( F \)[/tex] is proportional to [tex]\( \frac{1}{d^2} \)[/tex].

2. Original force and distance information:
The original gravitational force between the Earth and the satellite is 243 N, at some initial distance [tex]\( d \)[/tex].

3. Effect of increasing the distance by a factor of 4:
If the distance increases to 4 times the original distance (i.e., [tex]\( 4d \)[/tex]), then according to the inverse square law, the force will be reduced by a factor of [tex]\( (4)^2 \)[/tex].

4. Calculate the factor reduction:
[tex]\[ \text{Reduction factor} = 4^2 = 16 \][/tex]

5. Determine the new force:
The new force is obtained by dividing the original force by this factor:
[tex]\[ \text{New Force} = \frac{\text{Original Force}}{\text{Reduction Factor}} = \frac{243}{16} \][/tex]

6. Perform the division to find the precise force:
[tex]\[ \text{New Force} = \frac{243}{16} \approx 15.1875 \][/tex]

7. Round the result to the nearest whole number:
We round 15.1875 to the nearest whole number, which gives 15.

Conclusion:
The new gravitational force between the Earth and the satellite, when it is moved to 4 times the original distance, is approximately [tex]\( 15 \)[/tex] N.