Find a possible solution to the equation [tex]\sin (3x + 13) = \cos (4x)[/tex].

A. [tex]x = -13^{\circ}[/tex]
B. [tex]x = 0^{\circ}[/tex]
C. [tex]x = 11^{\circ}[/tex]
D. [tex]x = 13^{\circ}[/tex]

Please select the best answer from the choices provided:

A
B
C
D



Answer :

To solve the equation [tex]\(\sin(3x + 13^\circ) = \cos(4x)\)[/tex], we need to find an [tex]\(x\)[/tex] that satisfies this trigonometric identity.

First, recall the co-function identity: [tex]\(\cos(\theta) = \sin(90^\circ - \theta)\)[/tex]. Using this, we can rewrite [tex]\(\cos(4x)\)[/tex] in terms of sine:
[tex]\[ \cos(4x) = \sin\left(90^\circ - 4x\right) \][/tex]
Thus, the given equation transforms to:
[tex]\[ \sin(3x + 13^\circ) = \sin(90^\circ - 4x) \][/tex]

For this equality to hold, the arguments of the sine functions must either be equal or differ by multiples of [tex]\(180^\circ\)[/tex], due to the periodicity and symmetry of the sine function. Thus, we have two cases to consider:

Case 1:
[tex]\[ 3x + 13^\circ = 90^\circ - 4x + 360^\circ k \quad \text{for any integer } k \][/tex]

Simplifying,
[tex]\[ 3x + 4x = 90^\circ - 13^\circ + 360^\circ k \][/tex]
[tex]\[ 7x = 77^\circ + 360^\circ k \][/tex]
[tex]\[ x = 11^\circ + 51.43^\circ k \][/tex]

By considering integer values for [tex]\(k\)[/tex], we find that [tex]\(x = 11^\circ\)[/tex] is a possible solution.

Case 2:
[tex]\[ 3x + 13^\circ = 180^\circ - (90^\circ - 4x) + 360^\circ k \][/tex]
[tex]\[ 3x + 13^\circ = 90^\circ + 4x + 360^\circ k \][/tex]

Simplifying,
[tex]\[ 3x - 4x = 90^\circ - 13^\circ + 360^\circ k \][/tex]
[tex]\[ -x = 77^\circ + 360^\circ k \][/tex]
[tex]\[ x = -77^\circ - 360^\circ k \][/tex]

This scenario does not yield an [tex]\(x\)[/tex] within the provided answer choices as valid solutions.

Given the solutions derived from comprehensive analysis, [tex]\(x = 11^\circ\)[/tex] matches with the given answer choices.

Thus, the correct answer is:
[tex]\[ \boxed{11^\circ} \][/tex]