Ana exerts a force of [tex]$20 \, \text{N}$[/tex] on a volleyball that has a mass of [tex]$0.15 \, \text{kg}$[/tex]. What is the force that the volleyball exerts on Ana?

A. [tex]0.15 \, \text{N}[/tex]
B. [tex]20 \, \text{N}[/tex]
C. [tex]19.85 \, \text{N}[/tex]
D. [tex]20.15 \, \text{N}[/tex]



Answer :

Certainly! Let's break down the problem step-by-step using Newton's third law of motion.

### Newton's Third Law of Motion
Newton's third law of motion states that for every action, there is an equal and opposite reaction. This means that if Object A exerts a force on Object B, Object B exerts an equal and opposite force back on Object A.

### Given Data:
- The force Ana exerts on the volleyball (action force) is [tex]\( 20 \text{ N} \)[/tex].
- The mass of the volleyball is [tex]\( 0.15 \text{ kg} \)[/tex], but we do not need the mass for this particular question, as it's not relevant for Newton's third law.

### Applying Newton's Third Law
According to Newton's third law, the force that the volleyball exerts back on Ana (reaction force) must be equal in magnitude and opposite in direction to the force exerted by Ana on the volleyball.

Thus,
- The magnitude of the force that the volleyball exerts on Ana is [tex]\( 20 \text{ N} \)[/tex].

### Conclusion
- The force that the volleyball exerts on Ana is [tex]\( 20 \text{ N} \)[/tex].

Therefore, the correct answer is:
[tex]\[ 20 \text{ N} \][/tex]