Convert these unlike fractions to equivalent like fractions. If possible, reduce the final sum.

[tex]\[
\begin{array}{r}
\frac{1}{4} = \square \\
+\frac{5}{12} = \square \\
\hline
\square
\end{array}
\][/tex]



Answer :

Sure! Let's work through this step-by-step.

The problem involves adding two fractions, [tex]\(\frac{1}{4}\)[/tex] and [tex]\(\frac{5}{12}\)[/tex], and then reducing the final sum if possible.

### Step 1: Find the Least Common Multiple (LCM) of the Denominators

First, we need to determine the least common multiple (LCM) of the denominators of the fractions. The denominators are 4 and 12.

- The LCM of 4 and 12 is 12 (since 12 is the smallest number that both 4 and 12 divide into without a remainder).

### Step 2: Convert Fractions to Like Fractions

Next, we'll convert each fraction to an equivalent fraction with the common denominator of 12.

#### Convert [tex]\(\frac{1}{4}\)[/tex] to an equivalent fraction with denominator 12

To convert [tex]\(\frac{1}{4}\)[/tex] to a fraction with a denominator of 12, we multiply both the numerator and the denominator by the same number:

[tex]\[ \frac{1}{4} \times \frac{3}{3} = \frac{3}{12} \][/tex]

#### Convert [tex]\(\frac{5}{12}\)[/tex] to an equivalent fraction with denominator 12

The fraction [tex]\(\frac{5}{12}\)[/tex] already has the denominator 12, so it remains unchanged:

[tex]\[ \frac{5}{12} \][/tex]

### Step 3: Add the Like Fractions

Now we can add the fractions [tex]\(\frac{3}{12}\)[/tex] and [tex]\(\frac{5}{12}\)[/tex]:

[tex]\[ \frac{3}{12} + \frac{5}{12} = \frac{3 + 5}{12} = \frac{8}{12} \][/tex]

### Step 4: Reduce the Fraction (if possible)

Finally, we need to simplify [tex]\(\frac{8}{12}\)[/tex]. We do this by dividing the numerator and denominator by their greatest common divisor (GCD). The GCD of 8 and 12 is 4.

[tex]\[ \frac{8 \div 4}{12 \div 4} = \frac{2}{3} \][/tex]

### Result

So, the solution to the problem is:

- The equivalent like fractions are [tex]\(\frac{3}{12}\)[/tex] and [tex]\(\frac{5}{12}\)[/tex].
- The sum of the fractions is [tex]\(\frac{8}{12}\)[/tex], which simplifies to [tex]\(\frac{2}{3}\)[/tex].

Therefore, the final answer is:

[tex]\[ \boxed{\frac{2}{3}} \][/tex]