Answer :
To determine the type of image formed by a mirror when the magnification [tex]\( m \)[/tex] is given as [tex]\( m = -6.1 \)[/tex], we need to analyze the nature and properties of the magnification.
1. Sign of Magnification:
- The magnification [tex]\( m \)[/tex] is negative. This indicates that the image is real and inverted. In the context of mirrors, a real image is formed on the same side as the light actually converges.
2. Magnitude of Magnification:
- The magnitude of the magnification is [tex]\( |m| = 6.1 \)[/tex], which is greater than 1. This means the image is larger than the object.
3. Position Relative to the Mirror:
- Since the magnification is negative and the image is real, the image forms in front of the mirror.
Summarizing these points:
- The image is real (formed in front of the mirror).
- The image is inverted.
- The image is larger than the object.
Based on these characteristics, the correct choice is:
A. An image that is larger than the object and is in front of the mirror
1. Sign of Magnification:
- The magnification [tex]\( m \)[/tex] is negative. This indicates that the image is real and inverted. In the context of mirrors, a real image is formed on the same side as the light actually converges.
2. Magnitude of Magnification:
- The magnitude of the magnification is [tex]\( |m| = 6.1 \)[/tex], which is greater than 1. This means the image is larger than the object.
3. Position Relative to the Mirror:
- Since the magnification is negative and the image is real, the image forms in front of the mirror.
Summarizing these points:
- The image is real (formed in front of the mirror).
- The image is inverted.
- The image is larger than the object.
Based on these characteristics, the correct choice is:
A. An image that is larger than the object and is in front of the mirror