A person lifts a load of [tex]$400 N$[/tex] with the help of a lever by applying force at a distance of [tex]$2 m$[/tex] from the fulcrum. Find the value of mechanical advantage (MA), velocity ratio (VR), and efficiency.



Answer :

Sure, let's solve the problem step-by-step.

### Step 1: Mechanical Advantage (MA)
Mechanical Advantage (MA) is a measure of how much the lever amplifies the input effort force. It is defined as the ratio of the load force to the effort force.

Given:
- Load force (Load) = 400 N
- Effort force (Effort) = 400 N (for simplicity, we'll assume the effort force applied is equal to the load force)

[tex]\[ \text{MA} = \frac{\text{Load}}{\text{Effort}} = \frac{400 \, \text{N}}{400 \, \text{N}} = 1.0 \][/tex]

So, the Mechanical Advantage (MA) is [tex]\(1.0\)[/tex].

### Step 2: Velocity Ratio (VR)
Velocity Ratio (VR) is the ratio of the distance over which the effort is applied to the distance over which the load is moved.

Given:
- Effort distance = 2 meters
- Load distance = 1 meter (assuming for simplicity that the load distance is 1 meter)

[tex]\[ \text{VR} = \frac{\text{Effort distance}}{\text{Load distance}} = \frac{2 \, \text{m}}{1 \, \text{m}} = 2.0 \][/tex]

So, the Velocity Ratio (VR) is [tex]\(2.0\)[/tex].

### Step 3: Efficiency
Efficiency is the measure of how effectively the lever is working, and it is calculated by comparing the Mechanical Advantage to the Velocity Ratio. The formula for efficiency is:

[tex]\[ \text{Efficiency} (\%) = \left( \frac{\text{MA}}{\text{VR}} \right) \times 100\% \][/tex]

[tex]\[ \text{Efficiency} (\%) = \left( \frac{1.0}{2.0} \right) \times 100\% = 50.0\% \][/tex]

So, the efficiency of the lever is [tex]\(50.0\%\)[/tex].

### Summary:
- Mechanical Advantage (MA): [tex]\(1.0\)[/tex]
- Velocity Ratio (VR): [tex]\(2.0\)[/tex]
- Efficiency: [tex]\(50.0\%\)[/tex]

These are the values for the mechanical advantage, velocity ratio, and efficiency of the lever.