Answer:
24,211 tiles
Step-by-step explanation:
1. Convert wall dimensions to inches:
- Width: 2.5 m = 250 cm = 25000 mm (since 1 m = 1000 mm)
- Height: 4.0 m = 400 cm = 40000 mm
2. Convert these dimensions into inches:
- 1 inch = 25.4 mm, so:
- Width in inches = 25000 mm / 25.4 = 984.25 inches (approximately)
- Height in inches = 40000 mm / 25.4 = 1574.80 inches (approximately)
3. Calculate the area of the wall in square inches:
- Area = Width × Height = 984.25 inches × 1574.80 inches ≈ 1,549,885 square inches
4. Calculate the area covered by one tile:
- Each tile is 8 inches × 8 inches = 64 square inches
5. Determine the number of tiles needed:
- Number of tiles = Total area of wall / Area of one tile
- Number of tiles = 1,549,885 square inches / 64 square inches ≈ 24,211 tiles
Therefore, approximately 24,211 tiles of size 8" x 8" are needed to cover a wall that is 2.5 m wide and 4.0 m high.