Answer :

Answer:

24,211 tiles

Step-by-step explanation:

1. Convert wall dimensions to inches:

  - Width: 2.5 m = 250 cm = 25000 mm (since 1 m = 1000 mm)

  - Height: 4.0 m = 400 cm = 40000 mm

2. Convert these dimensions into inches:

  - 1 inch = 25.4 mm, so:

    - Width in inches = 25000 mm / 25.4 = 984.25 inches (approximately)

    - Height in inches = 40000 mm / 25.4 = 1574.80 inches (approximately)

3. Calculate the area of the wall in square inches:

  - Area = Width × Height = 984.25 inches × 1574.80 inches ≈ 1,549,885 square inches

4. Calculate the area covered by one tile:

  - Each tile is 8 inches × 8 inches = 64 square inches

5. Determine the number of tiles needed:

  - Number of tiles = Total area of wall / Area of one tile

  - Number of tiles = 1,549,885 square inches / 64 square inches ≈ 24,211 tiles

Therefore, approximately 24,211 tiles of size 8" x 8" are needed to cover a wall that is 2.5 m wide and 4.0 m high.