Sure! Let's solve the problem step-by-step:
Fred's serving ratio tells us that for every 2 serves that land in, 5 serves land out.
Given data:
- Number of serves that land in: 24
- Ratio of serves that land in to serves that land out: 2 : 5
To solve this, we need to find out how many units of 2 serves that land in and 5 serves that land out we have in those 24 successful serves.
1. Let's start by finding out how many sets of the serves Fred hit.
- Since the ratio is 2 serves in, we can calculate the number of sets by dividing the number of serves that land in by the in-ratio:
[tex]\( \text{number of sets} = \frac{\text{number of serves in}}{\text{in-ratio}} \)[/tex]
[tex]\[
\text{number of sets} = \frac{24}{2} = 12
\][/tex]
2. Now that we know Fred hit 12 sets of serves, each consisting of 2 successful serves and 5 unsuccessful ones, we can find out how many serves landed out by multiplying those sets with the out-ratio:
[tex]\[
\text{number of serves out} = \text{number of sets} \times \text{out-ratio}
\][/tex]
[tex]\[
\text{number of serves out} = 12 \times 5 = 60
\][/tex]
The number of serves that landed out is 60.
So the correct answer is:
O D. 60
