Answer:
To find the gradient of a straight line given by the equation \(5y = -3x + 1\), we need to rewrite the equation in the slope-intercept form, which is \(y = mx + c\), where \(m\) is the gradient (slope) of the line.
1. First, rearrange the given equation to the slope-intercept form:
5y = -3x+1
y=-x+0.5
2. Now, compare the equation with the slope-intercept form \(y mx + c\), we can see that the coefficient of \(x\) is the gradient of the line.
3. Therefore, the gradient of the line given by the equation \(5y = -3x + 1\) is \(-\frac{3}{5}\).
So, the gradient of the line is - 3.
