Answer:
To factorize the quadratic expression x^2-12x + 8, we need to
find two numbers that multiply to the constant term (8) and add
up to the coefficient of the linear term (-12). In this case, the
numbers are -2 and -6.
The factored form of x^2 - 12x +8 can be expressed as:
x^2 - 12x +8 = (x- 2)(x - 6)
Therefore, the solutions to the quadratic equation x^2- 12x + 8
=0 can be found by setting each factor to zero:
X-2=0 =>X=2
X -6= 0 =>x= 6
Hence, the solutions to the equation x^2 - 12x + 8 =0 are X = 2
and x = 6.
