Sure, let's solve the equation step by step.
We start with the given linear equation:
[tex]\[8x + 6y = 28\][/tex]
We are given the value of [tex]\(x\)[/tex]:
[tex]\[x = 11\][/tex]
Substituting [tex]\(x = 11\)[/tex] into the equation:
[tex]\[8(11) + 6y = 28\][/tex]
First, multiply 8 by 11:
[tex]\[88 + 6y = 28\][/tex]
Next, we need to isolate [tex]\(6y\)[/tex] on one side of the equation. To do this, subtract 88 from both sides of the equation:
[tex]\[6y = 28 - 88\][/tex]
Simplify the right side:
[tex]\[6y = -60\][/tex]
To solve for [tex]\(y\)[/tex], divide both sides by 6:
[tex]\[y = \frac{-60}{6}\][/tex]
This simplifies to:
[tex]\[y = -10\][/tex]
Therefore, the value of [tex]\(y\)[/tex] when [tex]\(x = 11\)[/tex] is [tex]\(-10\)[/tex].
