The hypotenuse of a [tex]$45^{\circ}-45^{\circ}-90^{\circ}$[/tex] triangle measures [tex]$22\sqrt{2}$[/tex] units.

What is the length of one leg of the triangle?

A. 11 units
B. [tex]$15 \sin$[/tex] units
C. 22 units
D. [tex]$22\sqrt{2}$[/tex] units



Answer :

Alright, let's go through this step-by-step to determine the length of one leg of a [tex]\(45^\circ-45^\circ-90^\circ\)[/tex] triangle when the hypotenuse is given as [tex]\(22\sqrt{2}\)[/tex] units.

1. Understand the Properties of the Triangle:
- In a [tex]\(45^\circ-45^\circ-90^\circ\)[/tex] triangle, the two legs are of equal length.
- The relationship between the legs and the hypotenuse can be described as follows: if each leg's length is [tex]\(a\)[/tex], then the hypotenuse is [tex]\(a\sqrt{2}\)[/tex].

2. Given:
- Hypotenuse = [tex]\(22\sqrt{2}\)[/tex] units

3. Relate Hypotenuse to Legs:
- Since the hypotenuse ([tex]\(c\)[/tex]) in a [tex]\(45^\circ-45^\circ-90^\circ\)[/tex] triangle is calculated from the leg ([tex]\(a\)[/tex]) using the formula [tex]\(c = a\sqrt{2}\)[/tex], we can set up the relationship:
[tex]\[ 22\sqrt{2} = a\sqrt{2} \][/tex]

4. Solve for [tex]\(a\)[/tex]:
- To isolate [tex]\(a\)[/tex], divide both sides of the equation by [tex]\(\sqrt{2}\)[/tex]:
[tex]\[ a = \frac{22\sqrt{2}}{\sqrt{2}} \][/tex]

5. Simplify:
- The [tex]\(\sqrt{2}\)[/tex] in the numerator and the denominator cancel each other out:
[tex]\[ a = 22 \][/tex]

6. Conclusion:
- The length of one leg of the triangle is 22 units.

So, the length of one leg of the [tex]\( 45^\circ-45^\circ-90^\circ \)[/tex] triangle, when the hypotenuse is [tex]\( 22\sqrt{2} \)[/tex] units, is [tex]\( \boxed{22} \)[/tex] units.