A bag contains 8 red marbles, 7 blue marbles, and 6 green marbles. Adam randomly picks out a marble from the bag.

What is the theoretical probability that Adam will pick a blue marble from the bag?

A. [tex]$\frac{2}{3}$[/tex]

B. [tex]$\frac{1}{3}$[/tex]

C. [tex]$\frac{1}{21}$[/tex]

D. [tex]$\frac{1}{7}$[/tex]



Answer :

To find the theoretical probability that Adam will pick a blue marble from the bag, we can proceed as follows:

1. Determine the total number of marbles in the bag:

The bag contains:
- 8 red marbles
- 7 blue marbles
- 6 green marbles

Adding these together gives us the total number of marbles:
[tex]\[ 8 + 7 + 6 = 21 \][/tex]

2. Identify the number of favorable outcomes:

In this case, the favorable outcome is picking a blue marble. There are 7 blue marbles in the bag.

3. Calculate the probability:

The probability [tex]\(P\)[/tex] of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes. Here, the probability [tex]\(P\)[/tex] of picking a blue marble is:
[tex]\[ P(\text{{blue marble}}) = \frac{\text{{number of blue marbles}}}{\text{{total number of marbles}}} \][/tex]
Substituting the values, we get:
[tex]\[ P(\text{{blue marble}}) = \frac{7}{21} \][/tex]

4. Simplify the fraction:

The fraction [tex]\(\frac{7}{21}\)[/tex] can be simplified by dividing both the numerator and the denominator by their greatest common divisor (GCD), which is 7:
[tex]\[ \frac{7 \div 7}{21 \div 7} = \frac{1}{3} \][/tex]

Therefore, the theoretical probability that Adam will pick a blue marble from the bag is:
[tex]\[ \boxed{\frac{1}{3}} \][/tex]