Helen draws a random circle and measures its diameter and circumference.

She gets a circumference, [tex]$C$[/tex], of [tex]$405 \, mm$[/tex] correct to 3 significant figures. She gets a diameter, [tex][tex]$d$[/tex][/tex], of [tex]$130 \, mm$[/tex] correct to 2 significant figures.

Helen wants to find the value of [tex]\pi[/tex] using the formula [tex]\pi = \frac{C}{d}[/tex].

Calculate the lower bound and upper bound for Helen's value of [tex]\pi[/tex].

Give your answers correct to 3 decimal places.



Answer :

To help Helen find the value of [tex]\(\pi\)[/tex] and its bounds, we'll start with the given measurements: a circumference [tex]\(C = 405\)[/tex] mm (correct to 3 significant figures) and a diameter [tex]\(d = 130\)[/tex] mm (correct to 2 significant figures). She wants to calculate [tex]\(\pi\)[/tex] using the formula:

[tex]\[ \pi = \frac{C}{d} \][/tex]

First, we find the estimated value of [tex]\(\pi\)[/tex]:

[tex]\[ \pi = \frac{405}{130} \approx 3.115 \][/tex]

Next, we need to determine the lower and upper bounds for the circumference and the diameter, then use these bounds to calculate the lower and upper bounds for [tex]\(\pi\)[/tex].

### Lower and Upper Bounds of Measurements
Since these measurements are given to 3 and 2 significant figures respectively, we can deduce:

- For the circumference [tex]\(C = 405\)[/tex] mm:
- Lower bound: [tex]\(404.5\)[/tex] mm
- Upper bound: [tex]\(405.5\)[/tex] mm

- For the diameter [tex]\(d = 130\)[/tex] mm:
- Lower bound: [tex]\(125\)[/tex] mm (slightly rounded down for a safe lower bound at 2 significant figures)
- Upper bound: [tex]\(135\)[/tex] mm (slightly rounded up for a safe upper bound at 2 significant figures)

### Calculating Bounds for [tex]\(\pi\)[/tex]

#### Lower Bound for [tex]\(\pi\)[/tex]:
To get the lower bound for [tex]\(\pi\)[/tex], divide the lower bound of circumference by the upper bound of diameter:

[tex]\[ \pi_{\text{lower}} = \frac{404.5}{135} \approx 2.996 \][/tex]

#### Upper Bound for [tex]\(\pi\)[/tex]:
To get the upper bound for [tex]\(\pi\)[/tex], divide the upper bound of circumference by the lower bound of diameter:

[tex]\[ \pi_{\text{upper}} = \frac{405.5}{125} \approx 3.244 \][/tex]

### Final Results
Rounds the values to 3 decimal places:

- Estimated value of [tex]\(\pi\)[/tex]: [tex]\(3.115\)[/tex]
- Lower bound for [tex]\(\pi\)[/tex]: [tex]\(2.996\)[/tex]
- Upper bound for [tex]\(\pi\)[/tex]: [tex]\(3.244\)[/tex]

Thus, Helen's calculated value of [tex]\(\pi\)[/tex] is approximately [tex]\(3.115\)[/tex] with bounds:

[tex]\[ \pi_{\text{lower}} = 2.996 \quad \text{and} \quad \pi_{\text{upper}} = 3.244 \][/tex]

So, the value of [tex]\(\pi\)[/tex] Helen gets using her measurements is [tex]\(3.115\)[/tex] bounded by [tex]\(2.996\)[/tex] and [tex]\(3.244\)[/tex], all to 3 decimal places.