Let's break down the problem step by step.
1. Understanding the given values:
- First, we need to establish the given values in the problem.
- We have a certain distance [tex]\(x\)[/tex] that is calculated as [tex]\(2 \times 240\)[/tex] meters.
- We also have a speed [tex]\(s\)[/tex] which is provided as 20 m/s.
- Additionally, the speed of light [tex]\(v_{\text{light}}\)[/tex] is given as [tex]\(3 \times 10^8\)[/tex] meters per second.
2. Calculating the values:
- We calculate the distance [tex]\(x\)[/tex]:
[tex]\[
x = 2 \times 240 = 480 \text{ meters}
\][/tex]
- The speed [tex]\(s\)[/tex] is directly given as:
[tex]\[
s = 20 \text{ m/s}
\][/tex]
- The speed of light is:
[tex]\[
v_{\text{light}} = 3 \times 10^8 \text{ m/s}
\][/tex]
3. Finding the required time [tex]\(t\)[/tex]:
- The problem involves finding a certain time related to moving at a certain speed.
- There is an equation provided which indicates that some time involving the speed of light and a varying parameter (not explicitly mentioned but deducible from context).
- The equation for time involves the following relationship:
[tex]\[
\text{time\_light\_speed} = \frac{-x \times 10^5}{s + 20}
\][/tex]
- Plugging in the values (where x = 480, s = 20):
[tex]\[
\text{time\_light\_speed} = \frac{-(480) \times 10^5}{20 + 20}
\][/tex]
- Simplifying the denominator:
[tex]\[
\text{time\_light\_speed} = \frac{-(480) \times 10^5}{40}
\][/tex]
- Performing the division:
[tex]\[
\text{time\_light\_speed} = \frac{-48000000}{40} = -1200000 \text{ seconds}
\][/tex]
4. Final Result:
- Based on this detailed calculation, we have deduced:
1. Distance [tex]\(x = 480 \, \text{meters}\)[/tex],
2. Speed [tex]\(s = 20 \, \text{m/s}\)[/tex],
3. Speed of light [tex]\(v_{\text{light}} = 3 \times 10^8 \, \text{m/s}\)[/tex],
4. Time at light speed [tex]\(\text{time\_light\_speed} = -1200000 \, \text{seconds}\)[/tex].
Hence, the detailed solution is consistent with the values derived and interpreted.
