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1st question is calculate the angular motion kinetic energy in Joules. Moment is of inertia is 0.060 kgm^2, traveling around 20 mi/hr, it makes 4.6 rev/sec which correspond to 2pi x 4.6 rad/sec. w=2pi rad/cycle.



Answer :

MathPhys

Answer:

25 J

Explanation:

Rotational kinetic energy (RE) is half the moment of inertia (I) times the square of the angular speed (ω). First, convert the angular speed to radians per second.

ω = 4.6 rev/s × (2π rad/rev)

ω = 9.2π rad/s

Calculate the rotational kinetic energy.

RE = ½ Iω²

RE = ½ (0.060 kg m²) (9.2π rad/s)²

RE ≈ 25 J

Rounded to two significant figures, the rotational kinetic energy is approximately 25 Joules.

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