Select the correct answer.

Two points located on [tex]$\overleftrightarrow{ JK }$[/tex] are [tex]$J(6,1)$[/tex] and [tex]$K(-3,8)$[/tex]. What is the slope of [tex]$\overleftrightarrow{ JK }$[/tex]?

A. [tex]$-\frac{9}{7}$[/tex]
B. [tex]$-\frac{7}{9}$[/tex]
C. [tex]$\frac{7}{9}$[/tex]
D. [tex]$\frac{9}{7}$[/tex]



Answer :

To determine the slope of the line passing through the points [tex]\( J(6,1) \)[/tex] and [tex]\( K(-3,8) \)[/tex], we use the slope formula:

[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

where [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] are the coordinates of the points. In our case:
[tex]\( J \)[/tex] has coordinates [tex]\((6, 1)\)[/tex] and [tex]\( K \)[/tex] has coordinates [tex]\((-3, 8)\)[/tex].

Substitute these coordinates into the slope formula:
[tex]\[ m = \frac{8 - 1}{-3 - 6} \][/tex]

Simplify the numerator and the denominator:
[tex]\[ m = \frac{7}{-9} \][/tex]

This simplifies to:
[tex]\[ m = -\frac{7}{9} \][/tex]

So, the slope of [tex]\(\overleftrightarrow{JK}\)[/tex] is [tex]\(-\frac{7}{9}\)[/tex].

Hence, the correct answer is:
[tex]\[ \boxed{-\frac{7}{9}} \][/tex]