Part 2 of 6
Points: 0.38 of 1

Ross Hopkins, president of Hopkins Hospitality, has developed the tasks, durations, and predecessor relationships in the following table for building new infrastructure.

\begin{tabular}{crrrc|ccccc}
\hline & \multicolumn{3}{c}{ Time (weeks) } & Immediate & & \multicolumn{3}{c}{ Time (weeks) } & Immediate \\
\cline { 2 - 8 } Activity & [tex]$a$[/tex] & [tex]$m$[/tex] & [tex]$b$[/tex] & Predecessor(s) & Activity & [tex]$a$[/tex] & [tex]$m$[/tex] & [tex]$b$[/tex] & Predecessor(s) \\
\hline A & 6 & 9 & 12 & - & G & 3 & 3 & 5 & C, E \\
B & 1 & 8 & 24 & A & H & 2 & 2 & 2 & F \\
C & 9 & 14 & 18 & A & I & 5 & 5 & 5 & F \\
D & 5 & 7 & 10 & A & J & 6 & 8 & 14 & D, G, H \\
E & 1 & 3 & 4 & B & K & 1 & 1 & 4 & I, J \\
F & 5 & 8 & 20 & C, E & & & & & \\
\hline
\end{tabular}

a) The expected (estimated) time for activity [tex]$C$[/tex] is 13.83 weeks. (Round your response to two decimal places.)

b) The variance for activity [tex]$C$[/tex] is [tex]$\square$[/tex] weeks. (Round your response to two decimal places.)



Answer :

To determine the variance for activity [tex]\(C\)[/tex], we can use the formula for variance in the Program Evaluation and Review Technique (PERT), which is given by:

[tex]\[ \text{Variance} = \left(\frac{b - a}{6}\right)^2 \][/tex]

where:
- [tex]\(a\)[/tex] is the optimistic time estimate,
- [tex]\(m\)[/tex] is the most likely time estimate,
- [tex]\(b\)[/tex] is the pessimistic time estimate.

Given the times for activity [tex]\(C\)[/tex]:
- [tex]\(a = 9\)[/tex] weeks,
- [tex]\(m = 14\)[/tex] weeks,
- [tex]\(b = 18\)[/tex] weeks,

we can substitute these values into the variance formula.

First, calculate [tex]\( \frac{b - a}{6} \)[/tex]:
[tex]\[ \frac{18 - 9}{6} = \frac{9}{6} = 1.5 \][/tex]

Next, square the result to find the variance:
[tex]\[ (1.5)^2 = 2.25 \][/tex]

Therefore, the variance for activity [tex]\(C\)[/tex] is [tex]\(2.25\)[/tex] weeks.