Two towns, A and B, are 440 km apart. A driver leaves Town A for Town B at an average speed of 60 km/h. Another driver leaves Town B for Town A at an average speed of 50 km/h at the same time. How long will it be before the drivers meet each other?



Answer :

Certainly! Let's solve this problem step-by-step.

1. Identify the Key Information:
- The distance between the two towns, A and B, is 440 km.
- Driver 1 travels from Town A to Town B at a speed of 60 km/h.
- Driver 2 travels from Town B to Town A at a speed of 50 km/h.
- Both drivers start their journey at the same time.

2. Understand the Problem:
- We need to find the time it will take for the two drivers to meet each other on the road.

3. Calculate the Relative Speed:
- Since both drivers are moving towards each other, their speeds are additive when determining how quickly the distance between them closes.
- Therefore, the combined or relative speed of the two drivers is:
[tex]\[ \text{Relative Speed} = 60 \, \text{km/h} + 50 \, \text{km/h} = 110 \, \text{km/h} \][/tex]

4. Determine the Time to Meet:
- The time it takes for the drivers to meet can be found using the formula:
[tex]\[ \text{Time} = \frac{\text{Distance}}{\text{Relative Speed}} \][/tex]
- Here, the distance between the towns is 440 km, and their relative speed is 110 km/h.
- Plugging in these values, we get:
[tex]\[ \text{Time} = \frac{440 \, \text{km}}{110 \, \text{km/h}} = 4 \, \text{hours} \][/tex]

5. Conclusion:
- The drivers will meet each other after 4 hours of travel.

Thus, it will be 4 hours before the drivers meet each other.