Answer :

To evaluate the limit [tex]\(\lim_{x \rightarrow \infty} \frac{3}{x^3 + 1}\)[/tex], we can proceed step by step, considering the behavior of the function as [tex]\(x\)[/tex] approaches infinity.

1. Understand the form of the function:
The given function is [tex]\(\frac{3}{x^3 + 1}\)[/tex]. As [tex]\(x\)[/tex] increases towards infinity, the term [tex]\(x^3 + 1\)[/tex] also increases significantly.

2. Analyze the denominator:
When [tex]\(x\)[/tex] becomes very large, the expression [tex]\(x^3 + 1\)[/tex] is dominated by the [tex]\(x^3\)[/tex] term. Hence, for very large [tex]\(x\)[/tex], we can approximate [tex]\(x^3 + 1 \approx x^3\)[/tex].

3. Simplified function analysis:
Thus, the function can be approximated as [tex]\(\frac{3}{x^3 + 1} \approx \frac{3}{x^3}\)[/tex] for large values of [tex]\(x\)[/tex].

4. Calculating the limit:
Now, we analyze the limit of the simpler function,

[tex]\[ \lim_{x \rightarrow \infty} \frac{3}{x^3} \][/tex]

As [tex]\(x\)[/tex] approaches infinity, [tex]\(x^3\)[/tex] also approaches infinity. Since [tex]\(3\)[/tex] is a constant, and the denominator [tex]\(x^3\)[/tex] grows without bound, the fraction [tex]\(\frac{3}{x^3}\)[/tex] becomes very small. Specifically, it approaches zero.

5. Conclusion:
Hence, the value of the limit is:

[tex]\[ \lim_{x \rightarrow \infty} \frac{3}{x^3 + 1} = 0 \][/tex]

Therefore, the limit is [tex]\(0\)[/tex].

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