Answer :

To calculate [tex]\(\frac{27b^2}{a^2}\)[/tex] given that [tex]\((a + 3b)(a - 3b) = 0\)[/tex], we can follow these steps:

1. Understand the given expression:
The expression given is [tex]\((a + 3b)(a - 3b) = 0\)[/tex].

2. Identify the pattern:
This expression is a difference of squares. The formula for the difference of squares is:
[tex]\[ (x + y)(x - y) = x^2 - y^2 \][/tex]
By comparing, we have [tex]\(x = a\)[/tex] and [tex]\(y = 3b\)[/tex]. So:
[tex]\[ (a + 3b)(a - 3b) = a^2 - (3b)^2 \][/tex]

3. Simplify the expression:
[tex]\[ a^2 - (3b)^2 = a^2 - 9b^2 \][/tex]
Given that [tex]\((a + 3b)(a - 3b) = 0\)[/tex], we have:
[tex]\[ a^2 - 9b^2 = 0 \][/tex]

4. Solve for [tex]\(a^2\)[/tex]:
To isolate [tex]\(a^2\)[/tex], add [tex]\(9b^2\)[/tex] to both sides:
[tex]\[ a^2 = 9b^2 \][/tex]

5. Calculate [tex]\(\frac{27b^2}{a^2}\)[/tex]:

- Substitute [tex]\(a^2 = 9b^2\)[/tex] into the expression [tex]\(\frac{27b^2}{a^2}\)[/tex]:
[tex]\[ \frac{27b^2}{a^2} = \frac{27b^2}{9b^2} \][/tex]

- Simplify the fraction:
[tex]\[ \frac{27b^2}{9b^2} = \frac{27}{9} = 3 \][/tex]

Thus, the value of [tex]\(\frac{27b^2}{a^2}\)[/tex] is:
[tex]\[ \boxed{27} \][/tex]