To solve for [tex]\( h \)[/tex] in the volume formula of a right square pyramid [tex]\( V = \frac{1}{3} a^2 h \)[/tex], let's go through the steps carefully.
1. The given equation is:
[tex]\[
V = \frac{1}{3} a^2 h
\][/tex]
2. To isolate [tex]\( h \)[/tex], we first need to eliminate the fraction. Multiply both sides of the equation by 3:
[tex]\[
3V = a^2 h
\][/tex]
3. Next, divide both sides of the equation by [tex]\( a^2 \)[/tex] to solve for [tex]\( h \)[/tex]:
[tex]\[
h = \frac{3V}{a^2}
\][/tex]
Thus, the correct equation that rewrites the formula to solve for [tex]\( h \)[/tex] is:
[tex]\[
h = \frac{3V}{a^2}
\][/tex]
Therefore, the correct choice is:
C. [tex]\( h = \frac{3V}{a^2} \)[/tex]
