Which explains how to find the radius of a circle whose equation is in the form [tex]$x^2 + y^2 = z$[/tex]?

A. The radius is the constant term, [tex]$z$[/tex].
B. The radius is the constant term, [tex][tex]$z$[/tex][/tex], divided by 2.
C. The radius is the square root of the constant term, [tex]$z$[/tex].
D. The radius is the square of the constant term, [tex]$z$[/tex].



Answer :

To solve this problem, we need to understand the standard form of the equation of a circle. The general form of a circle's equation centered at the origin is:

[tex]\[ x^2 + y^2 = r^2 \][/tex]

Here, [tex]\( r \)[/tex] represents the radius of the circle.

Given the equation:
[tex]\[ x^2 + y^2 = z \][/tex]

you can see that the equation is in the form [tex]\( x^2 + y^2 = r^2 \)[/tex]. By comparing both equations, we can directly infer that the constant term [tex]\( z \)[/tex] on the right side of the equation is equal to [tex]\( r^2 \)[/tex], the square of the radius.

To find the radius [tex]\( r \)[/tex], we need to take the square root of the constant term [tex]\( z \)[/tex]:

[tex]\[ r = \sqrt{z} \][/tex]

Thus, the radius is the square root of the constant term [tex]\( z \)[/tex].

Given a specific example where [tex]\( z = 25 \)[/tex]:

1. We recognize that the equation is [tex]\( x^2 + y^2 = 25 \)[/tex].
2. Here, [tex]\( z = 25 \)[/tex].
3. The radius [tex]\( r \)[/tex] is then [tex]\( \sqrt{25} \)[/tex].
4. Calculating [tex]\( \sqrt{25} \)[/tex] gives us [tex]\( 5 \)[/tex].

So, the radius of the circle is [tex]\( 5 \)[/tex].

Therefore, the correct answer to the problem is:
[tex]\[ \text{The radius is the square root of the constant term, } z. \][/tex]