Answered

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1. The number of moles in [tex]$22.4 \, L$[/tex] of [tex]$O_2$[/tex] at STP \\
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2. At STP, how much volume in liters does [tex]$3.4$[/tex] moles of [tex]$Xe$[/tex] take up? \\
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3. What volume at STP is occupied by [tex]$12.7$[/tex] moles of [tex]$PO_3$[/tex]? \\
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Answer :

GinnyAnswer
Let's solve the questions step-by-step.

### Step-by-Step Solution:

1. Understanding the Molar Volume at STP:
- At Standard Temperature and Pressure (STP), one mole of any ideal gas occupies 22.4 liters. This is a key fact that we will use for our calculations.

2. Question 11: Volume of Xenon (Xe) at STP for 3.4 moles:
- We need to find the volume that 3.4 moles of Xenon (Xe) will occupy at STP.
- Since 1 mole of any gas at STP occupies 22.4 liters, we calculate the volume for 3.4 moles by multiplying the number of moles by the molar volume:
- Volume of Xe at STP = [tex]\( \text{moles} \times \text{molar volume} \)[/tex]
- Volume of Xe at STP = [tex]\( 3.4 \, \text{moles} \times 22.4 \, \text{L/mole} \)[/tex]
- Volume of Xe at STP = 76.16 liters

3. Question 13: Volume of Phosgene (PO[tex]\(_3\)[/tex]) at STP for 12.7 moles:
- We need to find the volume that 12.7 moles of Phosgene (PO[tex]\(_3\)[/tex]) will occupy at STP.
- Again, using the molar volume at STP (22.4 liters per mole), we calculate the volume for 12.7 moles:
- Volume of PO[tex]\(_3\)[/tex] at STP = [tex]\( \text{moles} \times \text{molar volume} \)[/tex]
- Volume of PO[tex]\(_3\)[/tex] at STP = [tex]\( 12.7 \, \text{moles} \times 22.4 \, \text{L/mole} \)[/tex]
- Volume of PO[tex]\(_3\)[/tex] at STP = 284.48 liters

### Summary of Results:
- Volume of 3.4 moles of Xe at STP: 76.16 liters
- Volume of 12.7 moles of PO[tex]\(_3\)[/tex] at STP: 284.48 liters

These calculations demonstrate the volumes of the respective gases at STP based on the given number of moles and the molar volume constant.

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