Answered

If we apply Rolle's Theorem to the function [tex]f(x)=2x^2-16x-1[/tex] on the interval [tex][2,6][/tex], how many values of [tex]c[/tex] exist such that [tex]f^{\prime}(c)=0[/tex]?

What is the value of [tex]c[/tex]?
[tex]\square[/tex]



Answer :

To address the problem, we'll apply Rolle's Theorem to the function [tex]\( f(x) = 2x^2 - 16x - 1 \)[/tex] over the interval [tex]\([2, 6]\)[/tex]. Let's work through it step by step.

### Step 1: Verify the Conditions for Rolle's Theorem
Rolle's Theorem states that if a function [tex]\( f \)[/tex] is:
1. Continuous on a closed interval [tex]\([a, b]\)[/tex],
2. Differentiable on the open interval [tex]\((a, b)\)[/tex],
3. And [tex]\( f(a) = f(b) \)[/tex],

then there exists at least one [tex]\( c \)[/tex] in the interval [tex]\((a, b)\)[/tex] such that [tex]\( f'(c) = 0 \)[/tex].

First, we check that [tex]\( f(x) \)[/tex] is a polynomial, which is continuous and differentiable everywhere. Thus, conditions 1 and 2 are satisfied.

Next, we check if [tex]\( f(2) = f(6) \)[/tex]:
[tex]\[ f(2) = 2(2)^2 - 16(2) - 1 = 8 - 32 - 1 = -25 \][/tex]
[tex]\[ f(6) = 2(6)^2 - 16(6) - 1 = 72 - 96 - 1 = -25 \][/tex]
Since [tex]\( f(2) = f(6) = -25 \)[/tex], condition 3 is also met. Therefore, all conditions for Rolle's Theorem are satisfied.

### Step 2: Find the Derivative of [tex]\( f(x) \)[/tex]
Now, we need to find the derivative [tex]\( f'(x) \)[/tex]:
[tex]\[ f'(x) = \frac{d}{dx} (2x^2 - 16x - 1) = 4x - 16 \][/tex]

### Step 3: Find the Critical Points
Set the derivative equal to zero to find the critical points:
[tex]\[ 4x - 16 = 0 \][/tex]
[tex]\[ 4x = 16 \][/tex]
[tex]\[ x = 4 \][/tex]

### Step 4: Verify the Critical Point is Within the Interval
The critical point [tex]\( x = 4 \)[/tex] lies within the interval [tex]\([2, 6]\)[/tex]. Therefore, this is a valid value for [tex]\( c \)[/tex].

### Conclusion
There is exactly one value of [tex]\( c \)[/tex] such that [tex]\( f'(c) = 0 \)[/tex] within the interval [tex]\([2, 6]\)[/tex], and the value of [tex]\( c \)[/tex] is [tex]\( 4 \)[/tex].

Summary:
- Number of [tex]\( c \)[/tex] values: [tex]\( \boxed{1} \)[/tex]
- Value of [tex]\( c \)[/tex]: [tex]\( \boxed{4} \)[/tex]