What is the value of [tex]$y$[/tex] in the equation [tex]$6.4x + 2.8y = 44.4$[/tex] when [tex][tex]$x = 3$[/tex][/tex]?

A. [tex]y = 5[/tex]
B. [tex]y = 6[/tex]
C. [tex]y = 8[/tex]
D. [tex]y = 9[/tex]



Answer :

Let's find the value of [tex]\( y \)[/tex] in the given equation [tex]\( 6.4x + 2.8y = 44.4 \)[/tex] when [tex]\( x = 3 \)[/tex].

1. Substitute [tex]\( x = 3 \)[/tex] into the equation:
[tex]\[ 6.4(3) + 2.8y = 44.4 \][/tex]

2. Calculate [tex]\( 6.4 \times 3 \)[/tex]:
[tex]\[ 6.4 \times 3 = 19.2 \][/tex]

3. Replace [tex]\( 6.4 \times 3 \)[/tex] in the equation:
[tex]\[ 19.2 + 2.8y = 44.4 \][/tex]

4. Isolate the term with [tex]\( y \)[/tex] by subtracting 19.2 from both sides:
[tex]\[ 2.8y = 44.4 - 19.2 \][/tex]

5. Simplify the right-hand side:
[tex]\[ 44.4 - 19.2 = 25.2 \][/tex]

6. So the equation becomes:
[tex]\[ 2.8y = 25.2 \][/tex]

7. Solve for [tex]\( y \)[/tex] by dividing both sides by 2.8:
[tex]\[ y = \frac{25.2}{2.8} \][/tex]

8. Perform the division:
[tex]\[ y = 9 \][/tex]

Therefore, the value of [tex]\( y \)[/tex] when [tex]\( x = 3 \)[/tex] is [tex]\( y = 9 \)[/tex].

So, the correct answer is [tex]\( y = 9 \)[/tex].