Quadrilateral [tex]$JKLM$[/tex] has vertices [tex]$J(-7,-2)$[/tex], [tex]$K(-2,-2)$[/tex], [tex]$L(-3,-4)$[/tex], and [tex]$M(-6,-4)$[/tex]. Find the midpoints of each of the sides [tex]$\overline{JM}$[/tex] and [tex]$\overline{KL}$[/tex].

A. [tex]$M_{\overline{JM}}=(-0.5,1)$[/tex]; [tex]$M_{\overline{KL}}=(0.5,1)$[/tex]
B. [tex]$M_{\overline{JM}}=(-3,-6.5)$[/tex]; [tex]$M_{\overline{KL}}=(-3,-2.5)$[/tex]
C. [tex]$M_{\overline{JM}}=(-4.5,-4)$[/tex]; [tex]$M_{\overline{KL}}=(-2.5,-3)$[/tex]
D. [tex]$M_{\overline{JM}}=(-6.5,-3)$[/tex]; [tex]$M_{\overline{KL}}=(-2.5,-3)$[/tex]



Answer :

To find the midpoints of each of the sides [tex]\(\overline{JM}\)[/tex] and [tex]\(\overline{KL}\)[/tex] in quadrilateral [tex]\(J K L M\)[/tex] with vertices [tex]\(J(-7, -2)\)[/tex], [tex]\(K(-2, -2)\)[/tex], [tex]\(L(-3, -4)\)[/tex], and [tex]\(M(-6, -4)\)[/tex], we need to follow these steps:

1. Identify the coordinates of the vertices:
- [tex]\(J(-7, -2)\)[/tex]
- [tex]\(M(-6, -4)\)[/tex]
- [tex]\(K(-2, -2)\)[/tex]
- [tex]\(L(-3, -4)\)[/tex]

2. Calculate the midpoint of [tex]\(\overline{JM}\)[/tex]:
- To find the midpoint [tex]\((x_m, y_m)\)[/tex] of a line segment with endpoints [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex], use the midpoint formula:
[tex]\[ x_m = \frac{x_1 + x_2}{2}, \quad y_m = \frac{y_1 + y_2}{2} \][/tex]
- Applying this to [tex]\(\overline{JM}\)[/tex] where [tex]\(J(-7, -2)\)[/tex] and [tex]\(M(-6, -4)\)[/tex]:
[tex]\[ x_{JM} = \frac{-7 + (-6)}{2} = \frac{-13}{2} = -6.5 \][/tex]
[tex]\[ y_{JM} = \frac{-2 + (-4)}{2} = \frac{-6}{2} = -3 \][/tex]
- The midpoint of [tex]\(\overline{JM}\)[/tex] is [tex]\((-6.5, -3)\)[/tex].

3. Calculate the midpoint of [tex]\(\overline{KL}\)[/tex]:
- Using the same midpoint formula for [tex]\(\overline{KL}\)[/tex] where [tex]\(K(-2, -2)\)[/tex] and [tex]\(L(-3, -4)\)[/tex]:
[tex]\[ x_{KL} = \frac{-2 + (-3)}{2} = \frac{-5}{2} = -2.5 \][/tex]
[tex]\[ y_{KL} = \frac{-2 + (-4)}{2} = \frac{-6}{2} = -3 \][/tex]
- The midpoint of [tex]\(\overline{KL}\)[/tex] is [tex]\((-2.5, -3)\)[/tex].

So, the midpoints of the sides [tex]\(\overline{JM}\)[/tex] and [tex]\(\overline{KL}\)[/tex] are [tex]\((-6.5, -3)\)[/tex] and [tex]\((-2.5, -3)\)[/tex], respectively.

Thus, the correct answer is:
D. [tex]\( M_{\frac{JM}{JM}}(-6.5, -3); M_{\frac{KL}{KL}}(-2.5, -3) \)[/tex].