On the unit circle, where [tex]0\ \textless \ \theta \leq 2 \pi[/tex], when is [tex]\tan \theta[/tex] undefined?

A. [tex]\theta=\pi[/tex] and [tex]\theta=2 \pi[/tex]
B. [tex]\sin \theta=\cos \theta[/tex]
C. [tex]\theta=\frac{\pi}{2}[/tex] and [tex]\theta=\frac{3 \pi}{2}[/tex]
D. [tex]\sin \theta=\frac{1}{\cos \theta}[/tex]



Answer :

To determine when the tangent function [tex]\(\tan \theta\)[/tex] is undefined, we need to look for the values of [tex]\(\theta\)[/tex] where the denominator of the tangent function [tex]\(\cos \theta\)[/tex] is equal to zero. Recall that [tex]\(\tan \theta = \frac{\sin \theta}{\cos \theta}\)[/tex], and a fraction is undefined whenever its denominator is zero.

1. The unit circle and cosine function:
- The cosine function [tex]\(\cos \theta\)[/tex] is zero at [tex]\(\theta = \frac{\pi}{2}\)[/tex] and [tex]\(\theta = \frac{3\pi}{2}\)[/tex], within the interval [tex]\(0 < \theta \leq 2\pi\)[/tex].

2. Values of [tex]\(\theta\)[/tex] where [tex]\(\cos \theta = 0\)[/tex]:
- At [tex]\(\theta = \frac{\pi}{2}\)[/tex], the cosine function [tex]\(\cos \theta\)[/tex] is zero.
- At [tex]\(\theta = \frac{3\pi}{2}\)[/tex], the cosine function [tex]\(\cos \theta\)[/tex] is zero.

Therefore, [tex]\(\tan \theta\)[/tex] is undefined exactly at [tex]\(\theta = \frac{\pi}{2}\)[/tex] and [tex]\(\theta = \frac{3\pi}{2}\)[/tex] because these are the points where [tex]\(\cos \theta = 0\)[/tex].

So, the correct answer is:
[tex]\[ \theta = \frac{\pi}{2} \text{ and } \theta = \frac{3\pi}{2} \][/tex]