Answer :
To determine how many moles are contained in a certain number of grams of aspartame, you can use the formula:
[tex]\[ \text{Moles} = \frac{\text{Mass (g)}}{\text{Molar Mass} (g/mol)} \][/tex]
Given the molar mass of aspartame is 294.30 g/mol, let’s calculate the number of moles for each given mass of aspartame:
1. For 5.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{5.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.017 \text{ moles} \][/tex]
(rounded to three significant figures)
2. For 10.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{10.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.034 \text{ moles} \][/tex]
(rounded to three significant figures)
3. For 15.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{15.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.051 \text{ moles} \][/tex]
(rounded to three significant figures)
4. For 20.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{20.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.068 \text{ moles} \][/tex]
(rounded to three significant figures)
5. For 25.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{25.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.085 \text{ moles} \][/tex]
(rounded to three significant figures)
So, the calculated number of moles for each respective mass of aspartame are:
[tex]\[ 5.0 \text{ g} \rightarrow 0.017 \text{ moles} \][/tex]
[tex]\[ 10.0 \text{ g} \rightarrow 0.034 \text{ moles} \][/tex]
[tex]\[ 15.0 \text{ g} \rightarrow 0.051 \text{ moles} \][/tex]
[tex]\[ 20.0 \text{ g} \rightarrow 0.068 \text{ moles} \][/tex]
[tex]\[ 25.0 \text{ g} \rightarrow 0.085 \text{ moles} \][/tex]
[tex]\[ \text{Moles} = \frac{\text{Mass (g)}}{\text{Molar Mass} (g/mol)} \][/tex]
Given the molar mass of aspartame is 294.30 g/mol, let’s calculate the number of moles for each given mass of aspartame:
1. For 5.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{5.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.017 \text{ moles} \][/tex]
(rounded to three significant figures)
2. For 10.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{10.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.034 \text{ moles} \][/tex]
(rounded to three significant figures)
3. For 15.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{15.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.051 \text{ moles} \][/tex]
(rounded to three significant figures)
4. For 20.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{20.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.068 \text{ moles} \][/tex]
(rounded to three significant figures)
5. For 25.0 grams of aspartame:
[tex]\[ \text{Moles} = \frac{25.0 \text{ g}}{294.30 \text{ g/mol}} \][/tex]
[tex]\[ \approx 0.085 \text{ moles} \][/tex]
(rounded to three significant figures)
So, the calculated number of moles for each respective mass of aspartame are:
[tex]\[ 5.0 \text{ g} \rightarrow 0.017 \text{ moles} \][/tex]
[tex]\[ 10.0 \text{ g} \rightarrow 0.034 \text{ moles} \][/tex]
[tex]\[ 15.0 \text{ g} \rightarrow 0.051 \text{ moles} \][/tex]
[tex]\[ 20.0 \text{ g} \rightarrow 0.068 \text{ moles} \][/tex]
[tex]\[ 25.0 \text{ g} \rightarrow 0.085 \text{ moles} \][/tex]