Answer :
To determine the number of moles of copper (II) sulfate (CuSO₄) in a 0.125 g sample of CuSO₄, we can follow these steps:
1. Identify the given values:
- Mass of the CuSO₄ sample: 0.125 grams
- Molar mass of CuSO₄: 159.609 g/mol
2. Recall the formula for calculating moles:
[tex]\[ \text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} \][/tex]
3. Substitute the given values into the formula:
[tex]\[ \text{Moles of CuSO₄} = \frac{0.125 \text{ g}}{159.609 \text{ g/mol}} \][/tex]
4. Calculate the number of moles:
[tex]\[ \text{Moles of CuSO₄} \approx 0.00078 \text{ mol} \][/tex]
Therefore, the number of moles of copper (II) sulfate in a 0.125 g sample is approximately 0.00078 mol, which matches one of the given choices.
The correct answer is:
0.00078
1. Identify the given values:
- Mass of the CuSO₄ sample: 0.125 grams
- Molar mass of CuSO₄: 159.609 g/mol
2. Recall the formula for calculating moles:
[tex]\[ \text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} \][/tex]
3. Substitute the given values into the formula:
[tex]\[ \text{Moles of CuSO₄} = \frac{0.125 \text{ g}}{159.609 \text{ g/mol}} \][/tex]
4. Calculate the number of moles:
[tex]\[ \text{Moles of CuSO₄} \approx 0.00078 \text{ mol} \][/tex]
Therefore, the number of moles of copper (II) sulfate in a 0.125 g sample is approximately 0.00078 mol, which matches one of the given choices.
The correct answer is:
0.00078