Use the formula [tex]$S=n^2$[/tex] to find the sum of [tex]$1+3+5+\cdots+189$[/tex].

(Hint: To find [tex][tex]$n$[/tex][/tex], add 1 to the last term and divide by 2.)



Answer :

To find the sum of the series [tex]\(1 + 3 + 5 + \cdots + 189\)[/tex], we need to follow a few steps. This series is an arithmetic sequence of consecutive odd numbers. Let's break down the solution step by step:

1. Identify the Last Term:
The last term of the series is given as 189.

2. Find the Number of Terms ([tex]\(n\)[/tex]):
The nth term of the series of odd numbers can be expressed as [tex]\(2n - 1\)[/tex].
Here, the nth term is 189.

To find [tex]\(n\)[/tex], we set up the equation:
[tex]\[ 2n - 1 = 189 \][/tex]

3. Solve for [tex]\(n\)[/tex]:
Add 1 to both sides of the equation:
[tex]\[ 2n - 1 + 1 = 189 + 1 \][/tex]
[tex]\[ 2n = 190 \][/tex]

Now, divide by 2:
[tex]\[ n = \frac{190}{2} \][/tex]
[tex]\[ n = 95 \][/tex]

Thus, there are 95 terms in the series.

4. Use the Sum Formula:
The sum of the first [tex]\(n\)[/tex] odd numbers can be found using the formula:
[tex]\[ S = n^2 \][/tex]

Substitute [tex]\(n = 95\)[/tex] into the formula:
[tex]\[ S = 95^2 \][/tex]

5. Calculate the Sum:
Compute [tex]\(95^2\)[/tex]:
[tex]\[ 95 \times 95 = 9025 \][/tex]

Therefore, the sum of the series [tex]\( 1 + 3 + 5 + \cdots + 189 \)[/tex] is [tex]\( 9025 \)[/tex].

In summary:

- Number of terms ([tex]\(n\)[/tex]): 95
- Sum of the series ([tex]\(S\)[/tex]): 9025