Sure! Let's solve this problem step-by-step.
1. Identify the rates at which the taps fill water:
- The first tap fills water at a rate of [tex]\( 25 \)[/tex] liters per minute.
- The second tap fills water at a rate of [tex]\( 15 \)[/tex] liters per minute.
2. Determine the combined rate of both taps:
- When both taps are open, their rates will add up. So, the combined rate at which both taps fill the water tank is [tex]\( 25 + 15 = 40 \)[/tex] liters per minute.
3. Determine the time taken to fill the tank:
- Both taps are opened for [tex]\( 15 \)[/tex] minutes.
4. Calculate the volume of the water tank:
- The volume of the water tank can be found by multiplying the combined rate of water flow with the time both taps are open.
[tex]\[
\text{Volume of the water tank} = \text{Combined rate} \times \text{Time}
\][/tex]
[tex]\[
\text{Volume of the water tank} = 40 \, \text{liters per minute} \times 15 \, \text{minutes}
\][/tex]
[tex]\[
\text{Volume of the water tank} = 600 \, \text{liters}
\][/tex]
Therefore, the volume of the water tank is [tex]\( 600 \)[/tex] liters.
